The area of the ellipse `(x^(2))/(a^(2))+(y^(2))/(b^(2))=1` is

the equation of a diameter conjugate to a diameter y=(b)/(a)x of the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 is

The locus of poles of tangents to the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 with respect to concentric ellipse (x^(2))/(alpha^(2))+(y^(2))/(beta^(2))=1 is

If e' is the eccentricity of the ellipse (x^(2))/(a^(2)) + (y^(2))/(b^(2)) =1 (a gt b) , then

The locus of the point of intersection of tangents to the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 which meet at right , is

The eccentric angles of the ends of L.R. of the ellipse (x^(2)/(a^(2))) + (y^(2)/(b^(2))) = 1 is

If area of the ellipse (x^(2))/(16)+(y^(2))/(b^(2))=1 inscribed in a square of side length 5sqrt(2) is A, then (A)/(pi) equals to :

if the line x- 2y = 12 is tangent to the ellipse (x^(2))/(b^(2))+(y^(2))/(b^(2))=1 at the point (3,(-9)/(2)) then the length of the latusrectum of the ellipse is

If e is eccentricity of the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 (where,a lt b), then

The line y=x+rho (p is parameter) cuts the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 at P and Q, then prove that mid point of PQ lies on a^(2)y=-b^(2)x .

Find the eccentric angles of the extremities of the latus recta of the ellipse (x^2)/(a^2)+(y^2)/(b^2)=1