The area bounded by the x-axis, the curve `y=f(x),` and the lines `x=1,x=b` is equal to `sqrt(b^2+1)-sqrt(2)` for all `b >1,` then `f(x)` is

The area bounded by the X-axis, the cure y = f(x) and the lines x = 1 and x = b is equal to sqrt(b^(2)+1)-sqrt(2) for all b gt 1 then f(x) is

If the area bounded by the x-axis, the curve y=f(x), (f(x)gt0)" and the lines "x=1, x=b " is equal to "sqrt(b^(2)+1)-sqrt(2)" for all "bgt1, then find f(x).

The area bounded by the x-axis the curve y = f(x) and the lines x = a and x = b is equal to sqrt(b^(2) - a^(2)) AA b > a (a is constant). Find one such f(x).

The area bounded by the curve y=(1)/(sqrt(x)) and the lines x = 4 and x = 9 is

The area bounded by the curve y = x(x - 1)^2, the y-axis and the line y = 2 is

The area bounded by the curve y = (1)/(2)x^(2) , the X-axis and the lines x = 2 is

Area bounded by the line y=x, curve y=f(x),(f(x)gtx,AA xgt1) and the lines x=1,x=t is (t-sqrt(1+t^2)-(1+sqrt2)) for all tgt1 . Find f(x) .

The area bounded by the curve x = sin^(-1) y , the x-axis and the lines |x| = 1 is

The area bounded by the curve |x|=cos^-1y and the line |x|=1 and the x-axis is

The area bounded by the curve y^(2)=1-x and the lines y=([x])/(x),x=-1, and x=(1)/(2) is