Consider the two curves C(1):y=1+cos x a...

Consider the two curves `C_(1):y=1+cos x and C_(2): y=1 + cos (x-alpha)" for "alpha in (0,(pi)/(2))," where "x in [0,pi].` Also the area of the figure bounded by the curves `C_(1),C_(2), and x=0` is same as that of the figure bounded by `C_(2),y=1, and x=pi`.
The value of `alpha` is

Similar Questions

Explore conceptually related problems

The area of the figure bounded by the curves y^(2)=2x+1 and x-y-1=0 , is

The area of the figure bounded by y=e^(x-1),y=0,x=0 and x=2 is

Area bounded by the curves y=|x-1|, y=0 and |x|=2

Area bounded by the curves y=x^2 - 1 and x+y=3 is:

Find the area bounded by the curves x+2|y|=1 and x=0 .

Find the area of the region bounded by the curves 2y^2=x, 3y^2=x+1, y=0 .

The area of the closed figure bounded by the curves y=cosx,y =1+(2)/(pi)x and x=pi//2, is

The area of the region bounded by the curve C :y=(x+1)/(x^(2)+1) nad the line y=1 , is

The area of the region bounded by the curve y=x"sin"x, x-axis, x=0 and x=2pi is :