The area of bounded by `e^(ln(x+1)) ge |y|, |x| le 1` is….

The area bounded by |x| =1-y ^(2) and |x| +|y| =1 is:

The area bounded by y=e^(x) , Y-axis and the line y = e is

The area bounded by y=e^(x),y=e^(-x) and x = 2 is

The area of the region on place bounded by max (|x|,|y|) le 1/2 is

The area bounded by y=|log_(e)|x|| and y=0 is

The area bounded by the curves y=|x|-1 and y= -|x|+1 is

The area bounded by 4x^2 le y le 8x+12 is -

Sketch the region and find the area bounded by the curves |y+x|le1,|y-x|le1 and 2x^(2)+2y^(2)ge1 .

If the area bounded by the curves x^(2)+y^(2) le 4, x+y le 2, and y ge1 is (2pi)/(K)-(sqrtK)/(2)-(1)/(2)sq . units, then the value of K is equal to

STATEMENT-1 : The area bounded by the region {(x,y) : 0 le y le x^(2) + 1 , 0 le y le x + 1 , 0 le x le 2} is (23)/(9) sq. units and STATEMENT-2 : Required Area is int_(a)^(b) (y_(2) - y_(1)) dx