Home
Class 12
MATHS
Consider a curve y=f(x) in xy-plane. The...

Consider a curve y=f(x) in xy-plane. The curve passes through (0,0) and has the property that a segment of tangent drawn at any point P(x,f(x) and the line y=3 gets bisected by the line x+y=1. then the equation of curve, is

Promotional Banner

Similar Questions

Explore conceptually related problems

A curve passes through the point (3, -4) and the slope of the tangent to the curve at any point (x, y) is (-x/y) .find the equation of the curve.

Find the equation of a curve, passes through (-2,3) at which the slope of tangent at any point (x,y) is (2x)/(y^(2)) .

A curve has a property that the slope of the tangent at a point (x, y) is (y)/(x + 2y^(2)) and it passes through (1, 1). Find the equation of the curve.

Find the equation of a curve passing through (1,1) and whose slope of tangent at a point (x, y) is -(x)/(y) .

The curve y=f(x) in the first quadrant is such that the y - intercept of the tangent drawn at any point P is equal to twice the ordinate of P If y=f(x) passes through Q(2, 3) , then the equation of the curve is

A curve passes through the point (0,1) and the gradient at (x,y) on it is y(xy-1) . The equation of the curve is

Find the equation of the curve which passes through (1,0) and the slope of whose tangent at (x,y) is (x^2+y^2)/(2xy)

If a curve passes through the point (1, -2) and has slope of the tangent at any point (x,y) on it as (x^2-2y)/x , then the curve also passes through the point

If length of tangent at any point on the curve y=f(x) intercepted between the point and the x-axis is of length 1 . Find the equation of the curve.

lf length of tangent at any point on th curve y=f(x) intercepted between the point and the x-axis is of length 1. Find the equation of the curve.