`x^2(dy/dx)^2-2xy dy/dx+2y^2-x^2=0`

dy/dx+2xy=e^(-x^2)

dy/dx - y/x = 2x^2

Find order & degree of equation xy ((d^2y)/dx^2)+x(dy/dx)^2-y(dy/dx)=0 ,

y^2+x^2(dy)/(dx)=x y(dy)/(dx)

Solve the following differential equation: (x^2-2x y)\ dy+(x^2-3xy+2y^2)dx=0

(1-x^(2))(dy/dx)+xy=xy^(2)

(1-x^(2))(dy)/(dx)-2xy=x-x^(3)

If y=xlog(x/(a+b x)),t h e nx^3(d^2y)/(dx^2)= (a) x(dy)/(dx)-y (b) (x(dy)/(dx)-y)^2 y(dy)/(dx)-x (d) (y(dy)/(dx)-x)^2

If y=sin(logx) , prove that x^2(d^2y)/(dx^2)+x(dy)/(dx)+y=0 .

(x^2y^3+xy)dy=dx