Show that the equation of the curve passing through the point `(2,1)` and for which the sum of the subtangent and the abscissa is equal to 1 is `y(x-1)=1`.

The equation of the curve which passes through the point (2a, a) and for which the sum of the Cartesian sub tangent and the abscissa is equal to the constant a, is:

The equation of the curve through the point (1,1) and whose slope is (2ay)/(x(y-a)) is

Find the equation of the curve passing through the point (1,0) if the slope of the tangent to the curve at any point (x ,y)i s(y-1)/(x^2+x)dot

The equation of the curves through the point (1, 0) and whose slope is (y-1)/(x^2+x) is

Show that the equation of the circle which passes through the point (-1,7) and which touches the straight line x=y at (1,1) is x^2+y^2+3x-7y+2=0

Find the equation of a curve passing through the point (0, 1). If the slope of the tangent to the curve at any point (x, y) is equal to the sum of the x coordinate (abscissa) and the product of the x coordinate and y coordinate (ordinate) of that point.

Find the equation of a curve passing through the point (0, 1). If the slope of the tangent to the curve at any point (x, y) is equal to the sum of the x coordinate (abscissa) and the product of the x coordinate and y coordinate (ordinate) of that point.

Find the equation of a curve passing through the point (0, 1). If the slope of the tangent to the curve at any point (x, y) is equal to the sum of the x coordinate (abscissa) and the product of the x coordinate and y coordinate (ordinate) of that point.

Find the equation of a curve passing through the point (0, 1) if the slope of the tangent to the curve at any point (x, y) is equal to the sum of the x coordinate (abscissa) and the product of the x coordinate and y coordinate (ordinate) of that point.

Show that the equation of the curve passing through the point (1,0) and satisfying the differential equation (1+y^2)dx-xydy=0 is x^2-y^2=1