The curve represented by the differential equation `cosy(1-xcosy)dx-sinydy=0` satisyfing `y(0)=0` is (A) `tany=x^2` (B) `secy=x+1` (C) symmetric about x-axis (D) symmetric about y-axis

The curve represented by the differential equation (x^2+y^2+1)dx-2xydy=0 satisfying y(1)=1 is (A) x^2-y^2+x-1=0 (B) (x-1)^2+(y-2)^2=1 (C) a hyperbola (D) a circle

Which of the following are true for the curve represented by the differential equation sec^2y dy/dx+2x tany=x^3 satisfying y(1)=0 (A) equation of curve is 2tany=x^2-1 (B) equation of curve is y^2=x^3-1 (C) curve is a parabola (D) curve is not a conic

Consider the differential equation y^2dx+(x-1/y)dy=0 if y(1)=1 then x is

The solution of the differential equation x^(3)(dy)/(dx)+4x^(2) tany=e^(x) secy satisfying y(1)=0 , is

Solve the differential equation (dy)/(dx)=1+x+y^(2)+xy^(2) , when y=0 and x=0.

The general solution of the differential equation (y dx-x dy)/y=0 is(A) x y = C (B) x=C y^2 (C) y = C x (D) y=C x^2

The curve amongst the family of curves, represented by the differential equation (x^2-y^2)dx+2xydy=0 which passes through (1,1) is

The general solution of the differential equation (y dx-x dy)/y=0 is (A) x y" "=" "C (B) x=C y^2 (C) y" "=" "C x (D) y=C x^2

Solve the differential equation x(d^2y)/dx^2=1 , given that y=1, (dy)/(dx)=0 when x=1

The solution of the differential equation x(dy)/(dx) + 2y = x^2 (X ne 0) with y(1) =1, is :