Curves `y=f(x)` passing through the point `(0,1)` and `y=int_-oo^x f(t) dt` passing through the point `(0,1/n)` are such that the tangents drawn to them at the point with equal abscissae intersect on x axis. find Curve `y=f(x)`

Curves y=f(x) passing through the point (0,1) and y=int_-oo^x f(t) dt passing through the point (0,1/n) are such that the tangents drawn to them at the point with equal abscissae intersect on x-axis. Answer the question:The equation of curve y=f(x)

Given two curves: y=f(x) passing through the point (0,1) and g(x)=int_(-oo)^xf(t)dt passing through the point (0,1/n)dot The tangents drawn to both the curves at the points with equal abscissas intersect on the x-axis. Find the curve y=f(x)dot

Given the curves y=f(x) passing through the point (0,1) and y=int_(-oo)^(x) f(t) passing through the point (0,(1)/(2)) The tangents drawn to both the curves at the points with equal abscissae intersect on the x-axis. Then the curve y=f(x), is

The tangent to the curve y=xe^(x^2) passing through the point (1,e) also passes through the point

We are given the curves y=int_(-oo)^(x)f(t) dt through the point (0,(1)/(2)) and y=f(X), where f(x)gt0 and f(x) is differentiable, AAx in R through (0,1). If tangents drawn to both the curves at the point wiht equal abscissae intersect on the point on the X-axis, then int_(x to oo)(f(x))^f(-x) is

We are given the curves y=int_(-oo)^(x)f(t) dt through the point (0,(1)/(2)) and y=f(X), where f(x)gt0 and f(x) is differentiable, AAx in R through (0,1). If tangents drawn to both the curves at the point wiht equal abscissae intersect on the point on the X-axis, then The function f(x) is

We are given the curvers y=int_(- infty)^(x) f(t) dt through the point (0,(1)/(2)) any y=f(x) , where f(x) gt 0 and f(x) is differentiable , AA x in R through (0,1) Tangents drawn to both the curves at the points with equal abscissae intersect on the same point on the X- axists The number of solutions f(x) =2ex is equal to

Find the point of intersection of the tangents drawn to the curve x^2y=1-y at the points where it is intersected by the curve x y=1-ydot

Find the equation of a curve passing through the point (1, 1) , given that the segment of any tangent drawn to the curve between the point of tangency and the y-axis is bisected at the x-axis.

A curve passes through the point (3, -4) and the slope of the tangent to the curve at any point (x, y) is (-x/y) .find the equation of the curve.