If a curve passes through the point `(2,7/2)` and has slope `(1-1/x^2)` at any point `(x,y)` on it, then the ordinate of the point on the curve whose abscissa is `-2` is: (A) `5/2` (B) `3/2` (C) `-3/2` (D) `-5/2`

If a curve passes through the point (1, -2) and has slope of the tangent at any point (x,y) on it as (x^2-2y)/x , then the curve also passes through the point

Find the equation of the curve which passes through the point (3,-4) and has the slope (2y)/x at any point (x , y) on it.

A curve passes through the point (3, -4) and the slope of the tangent to the curve at any point (x, y) is (-x/y) .find the equation of the curve.

If the curve y=ax^(2)+bx+c passes through the point (1, 2) and the line y = x touches it at the origin, then

A curve passes through the point (2,-8) and the slope of tangent at any point (x,y) is given by x^(2)/2-6x . The maximum ordinate on the curve is given by lambda then find (3lambda ).

A curve passes through the point (5,3) and at any point (x,y) on it, the product of its slope and the ordinate is equal to its abscissa. Find the equation of the curve and identify it.

The equation of the curves through the point (1, 0) and whose slope is (y-1)/(x^2+x) is

The chord joining the points where x = p and x = q on the curve y = ax^(2)+bx+c is parallel to the tangent at the point on the curve whose abscissa is

The equation of the curve through the point (1,1) and whose slope is (2ay)/(x(y-a)) is

Let C be a curve passing through M(2,2) such that the slope of the tangent at any point to the curve is reciprocal of the ordinate of the point. If the area bounded by curve C and line x=2 is A, then the value of (3A)/(2) is__.