A curve passes through the point `(1,(pi)/(6)).` Let the slope of the curve at eact point (x,y) be `(y)/(x)+sec((y)/(x)),xgt0.` Then, the equation of the curve is

A curve passes through the point (1,(pi)/(6)). Let the slope of the curve at each point (x,y) be (y)/(x)+sec((y)/(x)),xgt0. Then, the equation of the curve is

A curve passes through the point (1,pi/6) . Let the slope of the curve at each point (x , y) be y/x+sec(y/x),x > 0. Then the equation of the curve is

A curve passes through the point (3, -4) and the slope of the tangent to the curve at any point (x, y) is (-x/y) .find the equation of the curve.

If slope of the tangent at the point (x, y) on the curve is (y-1)/(x^(2)+x) , then the equation of the curve passing through M(1, 0) is :

A curve passes through the point (2,-8) and the slope of tangent at any point (x,y) is given by x^(2)/2-6x . The maximum ordinate on the curve is given by lambda then find (3lambda ).

If a curve passes through the point (1, -2) and has slope of the tangent at any point (x,y) on it as (x^2-2y)/x , then the curve also passes through the point

Find the equation of a curve passing through the point (0, 1). If the slope of the tangent to the curve at any point (x, y) is equal to the sum of the x coordinate (abscissa) and the product of the x coordinate and y coordinate (ordinate) of that point.

Find the equation of a curve passing through the point (0, 1). If the slope of the tangent to the curve at any point (x, y) is equal to the sum of the x coordinate (abscissa) and the product of the x coordinate and y coordinate (ordinate) of that point.

Find the equation of a curve passing through the point (0, 1). If the slope of the tangent to the curve at any point (x, y) is equal to the sum of the x coordinate (abscissa) and the product of the x coordinate and y coordinate (ordinate) of that point.

The equation of the curve passing through the point (1,pi/4) and having a slope of tangent at any point (x,y) as y/x - cos^2(y/x) is