If `6/5 a^A-3^B=9^C` where `A=log_a x.log_(10) alog_a 5,B=log_(10) (x/10)` and `C=log_(100) x+log_4 2`. Find x

If log_(10)5=a and log_(10)3=b ,then

if x+log_10 (1+2^x)=xlog_10 5+log_10 6 then x

(6)/(5)a^((log_(a)x)(log_(10)a)(log_(a)5))-3^(log_(10)((x)/(10)))=9^(log_(100)x+log_(4)2) (where a gt 0, a ne 1) , then log_(3)x=alpha +beta, alpha is integer, beta in [0, 1) , then alpha=

Solve log_(6) 9-log_(9) 27 + log_(8)x = log_(64) x - log_(6) 4 ..

Solve log_(6) 9-log_(9) 27 + log_(8)x = log_(64) x - log_(6) 4 ..

(6)/(5)a^((log_(a)x)(log_(10)a)(log_(a)5))-3^(log_(10)((x)/(10)))=9^(log_(100)x+log_(4)2)("where "a gt 0, a ne 1) , then log_(3)x=alpha +beta, alpha is integer, beta in [0, 1) , then alpha=

Solve (log_(3)x)(log_(5)9)- log_x 25 + log_(3) 2 = log_(3) 54 .

Given 2 log_(10) x + 1 = log_(10) 250 , find : (i) x (ii) log_(10) 2x

Find the domain f(x)=log_(100x)((2 log_(10) x+1)/-x)

If y=log_(10)x+log_(e)x+log_(10)10 , then find (dy)/(dx)