If `log_2 x+log_2yge6`prove that the smallest possible value of x+y is 16.

If log_(10)x +log_(10)y le 2 then smallest possible value of x + y is P . Then (P)/(10) is

If (log)_2x+(log)_2ygeq6, then the least value of x+y is 4 (b) 8 (d) 16 (d) 32

if log_2 x+ log_2 y >= 6 then the least value of x+y

There exists a positive number k such that log_2x+ log_4x+ log_8x= log_kx , for all positive real no x. If k= a^(1/b) where (a,b) epsilon N, the smallest possible value of (a+b)= (C) 12 A) 75 (B) 65 (D) 63_

If log_(y) x + log_(x) y = 2, x^(2)+y = 12 , then the value of xy is

If log_y x +log_x y=7, then the value of (log_y x)^2+(log_x y)^2, is

If log_2 (log_2 (log_3 x)) = log_2 (log_3 (log_2 y))=0 , then the value of (x+y) is

Let x,y,z be positive real numbers such that log_(2x)z=3, log_(5y)z=6 and log_(xy)z=2/3 then the value of z is

Let (log_(x)(2a-x))/(log_(x)2)+(log_(a)(x))/(log_(a)2)=(1)/(log_(a^(2)-1)2) . Then sum of possible value(s) of a for which equation has only one solution, willlie in interval

If the equation (log_(12)(log_(8)(log_(4)x)))/(log_(5)(log_(4)(log_(y)(log_(2)x))))=0 has a solution for 'x' when c lt y lt b, y ne a , where 'b' is as large as possible, then the value of (a+b+c) is equals to :