If `T_n =sin^n theta+cos^n theta,` then `(T_6-T_4)/T_6 =m` holds for values of `m` satisfying (A) `m in [-1, 1/3]` (B) `m in [0, 1/3]` (C) `m in [-1,0]` (D) `m in [-1, - 1/2]`

If T_(n)=cos^(n)theta+sin ^(n)theta, then 2T_(6)-3T_(4)+1=

If T_n=sin^n x+cos^n x , prove that 2T_6-3T_4+1=0

If sintheta +cos theta =m and sec theta + cosec theta =n then n(m+1)(m-1) equals

The mid-point of the segment joining (3m, 6) and (-4, 3n) is (1, 2m, -1). Find the values of m and n.

If l : m = 2 (1)/(2) : 1(2)/(3) and m : n = 1 (1)/(4) : 3 (1)/(2) , find l : m : n

If [x] denotes the integral part of x and m= [|x|/(1+x^2)],n= integral values of 1/(2-sin3x) then (A) m!=n (B) mgtn (C) m+n=0 (D) n^m=0

If I(m,n)=int_0^1 t^m(1+t)^n.dt , then the expression for I(m,n) in terms of I(m+1,n-1) is:

If sin A + cos A = m and sin^3 A + cos^3A=n , then (1) m^3-3m + n = 0 (2) n^3-3n + 2m=0 (3) m^3-3m + 2n = 0 (4) m3 + 3m + 2n = 0

Let f^(prime)(x)=(192 x^3)/(2+sin^4pix)fora l lx in Rw i t hf(1/2)=0.Ifmlt=int_(1/2)^1f(x)dxlt=M , then the possible values of ma n dM are (a) m=13 ,M=24 (b) m=1/4,M=1/2 (c) m=-11 ,M=0 (d) m=1,M=12

Let l= sin theta, m=cos theta and n=tan theta . Q. If theta=-1042^(@) , then : (a) n>1 (b) n<1 (c) n=1 (d) nothing can be said