If cot theta+tan theta = x and sec theta...

If `cot theta+tan theta = x` and `sec theta-cos theta=y`, then show that `sin thetacos theta=1/x` or `sin theta cos theta=1/x` or `sin theta* tan theta=y` or `(x^(2)y)^(2//3)-(xy^(2))^(2//3)-(xy^(2))^(2//3)=1`.

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