If `3cosalpha=2cos(alpha-2beta),` then `tan(alpha-beta) tanbeta=` (A) 5 (B) -5 (C) `1/5` (D) `-1/5`

If 5 sinalpha=3"sin"(alpha+2beta)!=0, then tan(alpha+beta) is equal to

If cos alpha=(2cos beta-1)/(2-cos beta) then tan (alpha/2) is equal to

If 3 sin alpha=5 sin beta , then (tan((alpha+beta)/2))/(tan ((alpha-beta)/2))=

cos(alpha+beta)+sin(alpha-beta)=0"and"tanbeta=1/2009 ,find tan(alpha)

cos 2 alpha =(3 cos 2 beta -1)/( 3-cos 2 beta), then tan alpha=

If "cot"(alpha+beta)=0, then "sin"(alpha+2beta) can be (a) -sinalpha (b) sinbeta (c) cosalpha (d) cosbeta

If sin alpha+sin beta=a and cos alpha-cos beta=b then tan((alpha-beta)/2) is equal to-

cos(alpha+beta)+sin(alpha-beta)=0"and"tanbeta=1/2009 then value of tan3α

Find the value of sin (alpha - beta), cos (alpha -beta) and tan (alpha - beta), given sin alpha = (8)/(17) , tan beta = (5)/(12), alpha and beta in Quadrant I.

If sin alpha+sin beta=a\ a n d\ cosalpha-cosbeta=b , then tan(alpha-beta)/2= -a/b b. b/a c. sqrt(a^2+b^2) d. none of these