It `cos(alpha+beta)=4/5,sin(alpha-beta)=5/(13)a n dalpha,beta` lie between `0a n dpi/4` , prove that `tan2alpha=(56)/(33)`

If cos(alpha+beta)=4/5; sin(alpha-beta)=5/13 and alpha,beta lie between 0&pi/4 then find the value of tan2alpha

If cos(alpha+beta)=0 then sin(alpha+2beta)=

If cos (alpha + beta) = (4)/(5), sin (alpha - beta) = (5)/(13) and alpha and beta lie between 0 and (pi)/(4) , find tan 2 alpha .

Let cos(alpha+beta)""=4/5 and let sin (alpha-beta)""=5/(13) where 0lt=alpha,betalt=pi/4 , then t a n""2alpha= (1) (56)/(33) (2) (19)/(12) (3) (20)/7 (4) (25)/(16)

If cos(alpha+beta)=(4)/(5) and sin(alpha-beta)=(5)/(13) , where alpha lie between 0 and (pi)/(4) , then find that value of tan2alpha .

If sin (alpha + beta) = 4/5 , sin (alpha -beta) = (5)/(13), alpha + beta , alpha - beta being acute angles prove that tan 2 alpha = (63)/(16).

Let cos (alpha+beta) = 4/5 and sin(alpha-beta)=5/13 where 0<= alpha,beta<= pi/4 then find tan (2alpha)

cos(alpha+beta)+sin(alpha-beta)=0"and"tanbeta=1/2009 ,find tan(alpha)

If cos(alpha+beta)+sin(alpha-beta)=0 and tan beta ne1 , then find the value of tan alpha .

If sin (alpha + beta) = 4/5 , cos (alpha - beta) = (12)/(13) 0 lt alpha lt (pi)/(4), 0 lt beta lt (pi)/(4), find tan 2 alpha .