If `sin(alpha+beta)=1, sin(alpha-beta)=1/2` then, `tan(alpha+2beta) tan(2alpha+beta)` is equal to :

If : sin (alpha + beta)=1 and sin (alpha-beta)=(1)/(2), "then" : tan (alpha+2beta)*tan(2alpha+beta)=

If tan(2alpha+beta)=x & tan(alpha+2beta)=y , then [ tan3(alpha+beta)]. [ tan(alpha-beta)] is equal to (wherever defined)

If "sin" alpha=ksinbeta then tan((alpha-beta)/(2)).cot((alpha+beta)/(2)) is equal to

If 5 sinalpha=3"sin"(alpha+2beta)!=0, then tan(alpha+beta) is equal to

If sin (alpha + beta) = 4/5 , sin (alpha -beta) = (5)/(13), alpha + beta , alpha - beta being acute angles prove that tan 2 alpha = (63)/(16).

If cos( alpha+beta) + sin(alpha-beta) = 0 and 2010tan beta - 1 = 0 then tan alpha is equal to

If sin(alpha+beta)=1 and sin(alpha-beta)=1/2 , where 0lt=alpha, betalt= pi/2 , then find the values of tan(alpha+2beta) and tan(2alpha+beta) .

If sin alpha + sin beta=a and cos alpha+cosbeta=b then tan((alpha-beta)/2) is equal to

If (tanalpha+tanbeta)/(cot alpha+cot beta)+{cos(alpha-beta)+1}^(-1)=1, then tan alpha tan beta is equal to

If cot (alpha + beta) = 0 , then sin (alpha + 2 beta) is equal to