In an acute-angled triangle ABC, `tanA+tanB+tanC`

In an acute angled triangle ABC , let AD, BE and CF be the perpendicular opposite sides of the triangle. The ratio of the product of the side lengths of the triangles DEF and ABC , is equal to

In an acute angle triangle ABC, AD, BE and CF are the altitudes, then (EF)/a+(FD)/b+(DE)/c is equal to -

In an acute angled triangle ABC , the minimum value of tanA tanB tanC is

Prove that in an acute angled triangle ABC, the least values of Sigma secA and Sigma tan^2 A are 6 and 9 respectively.

In acute angled triangle ABC prove that tan ^(2)A+tan^(2)B+tan^(2)Cge9 .

Prove that in an acute angled triangle ABC , sec A+sec B +sec Cge 6 .

Statement-1: In an acute angled triangle minimum value of tan alpha + tanbeta + tan gamma is 3sqrt(3) . And Statement-2: If a,b,c are three positive real numbers then (a+b+c)/3 ge sqrt(abc) into in a triangleABC , tanA+ tanB + tanC= tanA. tanB.tanC

If in a triangle ABC, (tanA)/1= (tanB)/2 = (tanC)/3 then prove that 6sqrt(2a)=3sqrt(5b)=2sqrt(10)c

In an acute angled triangle ABC, r + r_(1) = r_(2) + r_(3) and angleB gt (pi)/(3) , then

In an acute angle Delta ABC, let AD, BE and CF be the perpendicular from A, B and C upon the opposite sides of the triangle. (All symbols used have usual meaning in a tiangle.) The orthocentre of the Delta ABC, is the