If in a triamgle ABC, `theta` is the angle determined by `cos theta=(a-b)//c`, then

If in a triangle ABC, theta is the angle determined by cos theta=(a-b)//c , then

In a triangleABC"if c"=(a+b) sin theta and cos theta=(ksqrtab)/(a+b)," then "k=

In a triangle ABC, prove that for any angle theta, b cos (A - theta) + a cos (B + theta) = C cos theta .

If the angle theta is acute, then the acute angle between x^(2)(cos theta-sin theta)+2xy cos theta+y^(2)(cos theta+sin theta)=0, is

In a triangle ABC, sin A- cos B = Cos C , then angle B is

The locus of the points of intersection of the lines x cos theta+y sin theta=a and x sin theta-y cos theta=b , ( theta= variable) is :

For all theta, tan theta+ cos theta + tan (-theta) + cos(-theta)=

In a triangle ABC, (c cos(A-theta) + acos (C + theta))/(b costheta) is equal to

If theta=-1000^(@) , determine the sign of theta-cos theta .

In Figure, A D=D B \ and \ /_B is a right angle. Determine. (a)\ sin theta quad (b)\ cos theta quad (c)\ tan theta quad (d)\ sin^2 theta+cos^2 theta