The sides of a triangle are `3x + 4y, 4x + 3y` and `5x+5y` units, where `x gt 0, y gt 0`. The triangle is

If the equations of three sides of a triangle are x+y=1, 3x + 5y = 2 and x - y = 0 then the orthocentre of the triangle lies on the line/lines

The equaiton of the lines representing the sides of a triangle are 3x - 4y =0 , x+y=0 and 2x - 3y = 7 . The line 3x + 2y = 0 always passes through the

The sides of a triangle are given by x-2y+9=0, 3x+y-22=0 and x+5y+2=0 . Find the vertices of the triangle.

The sides of a triangle are given by the equations 3x+4y=10, 4x-3y=5, and 7x+y+10=0 , show that the origin lies within the triangle.

The sides of a triangle ABC lie on the lines 3x + 4y = 0, 4x +3y =0 and x =3 . Let (h, k) be the centre of the circle inscribed in triangleABC . The value of (h+ k) equals

The coordinates of the vertices of a triangle are (4, -3), (-5, 2) and (x, y). If the centroid of the triangle is at the origin, show that x=y=1 .

If two sides of a triangle are represented by 2x-3y+4=0 and 3x+2y-3=0 , then its orthocentre lies on the line : (A) x-y+ 8/15 = 0 (B) 3x-2y+1=0 (C) 9x-y+9/13 = 0 (D) 4x+3y+5/13=0

In triangle A B C , the equation of side B C is x-y=0. The circumcenter and orthocentre of triangle are (2, 3) and (5, 8), respectively. The equation of the circumcirle of the triangle is a) x^2+y^2-4x+6y-27=0 b) x^2+y^2-4x-6y-27=0 c) x^2+y^2+4x-6y-27=0 d) x^2+y^2+4x+6y-27=0

The equations of the sides of a triangle are x+y-5=0, x-y+1=0, and y-1=0. Then the coordinates of the circumcenter are

The base and the altitude of a triangle are (3x - 4y) and (6x + 5y) respectively. Find its area.