If twice the square of the diameter of the circle is equal to half the sum of the squares of the sides of incribed triangle ABC,then `sin^(2)A+sin^(2)B+sin^(2)C` is equal to

In a right angled triangle ABC sin^(2)A+sin^(2)B+sin^(2)C=

In any triangle ABC b^(2)sin2C+c^(2)sin2B=

If A, B, C are the angles of a triangle such that sin^(2)A+sin^(2)B=sin^(2)C , then

If Delta denotes the area of DeltaABC , then b^(2) sin 2C + c^(2) sin 2B is equal to

Prove that three times the sum of the squares of the sides of a triangle is equal to four times the sum of the squares of the medians of the triangle.

If the square of one side of a triangle is equal to the sum of the squares of the other two sides then the triangle is a right triangle with the angle opposite the first sides as right angle.

In any DeltaABC, sum a^(2) (sin^2 B - sin^2 C) =

In a right angled triangle ABC, write the value of sin^2 A + sin^2 B+ sin^2C

(sin2A+sin2B+sin2C)/(sinA+sinB +sinC) is equal to

If sin theta and - cos theta are the roots of the equation ax^2-bx-c=0 where a, b and c the side of a triangle ABC , then cos B is equal to :-