In a triangle ABC, points D and E are ta...

In a triangle ABC, points D and E are taken on side BC such that BD= DE= EC. If angle ADE = angle AED = `theta`, then: (A) tan `theta`= 3 tan B (B) 3 tan `theta` = tan C (C) (6tan `theta`)/(`tan^2` `theta`-9)= tanA (D) `angleB`=`angle C`

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