ABC is a triangle and D is the middle point of BC. If AD is perpendicular to AC, then prove that `cos A . cos C =(2(c^(2)-a^(2)))/(3ac)`

A B C is a triangle. D is the mid point of B Cdot If A D is perpendicular to A C , then prove that cos A\ dotcos C=(2(c^2-a^2))/(3a c) .

ABC is a triangle. D is the middle point of BC. If AD is perpendicular to AC, The value of cos A cos C , is

In the figure, AD is perpendicular to BC, prove that AB+AC gt 2AD .

D is midpoint of BC in Delta ABC such that AD and AC are perpendicular, Show that Cos A Cos C = (2 (c^2-a^2))/(3ac)

In triangle ABC, AB > AC. E is the mid-point of BC and AD is perpendicular to BC. Prove that : AB^2 +AC^2=2AE^2 +2BE^2

The given figure shows a triangle ABC, in which AB gt AC . E is the mid-point of BC and AD is perpendicular to BC. Prove that AB^(2)- AC^(2)= 2BCxxED .

The given figure shows a triangle ABC, in which AB gt AC. E is the mid-point of BC and AD is perpendicular to BC. Prove that : AB^(2) +AC^(2) =2BE^2 +2AE^2

If D id the mid-point of the side BC of a triangle ABC and AD is perpendicular to AC , then

In the figure AB = BC and AD is perpendicular to CD. Prove that : " "AC^(2)=2.BC.DC

ABC is a right angled triangle with ABC = 90^@ . D is any point on AB and DE is perpendicular to AC. Prove that: If AC = 13 cm, BC = 5 cm and AE = 4 cm. Find DE and AD.