AB is a diameter of a circle and C is any point on the circumference of the circle. Then a) the area of ` A B C` is maximum when it is isosceles b) the area of ` A B C` is minimum when it is isosceles c) the perimeter of ` A B C` is minimum when it is isosceles d) none of these

AB is a diameter of a circle and C is any point on the circumference of the circle. Then (a) the area of DeltaABC is maximum when it is isosceles (b) the area of DeltaABC is minimum when it is isosceles (c) the perimeter of DeltaABC is minimum when it is isosceles (d) none of these

A B is a diameter of a circle and C is any point on the circle. Show that the area of A B C is maximum, when it is isosceles.

If A is the area and C is the circumference of a circle, then its radius is (a) A/C (b) (2A)/C (c) (3A)/C (d) (4A)/C

If D is any point on the base B C produced, of an isosceles triangle A B C , prove that A D > A B .

A B C is a triangle and D is the mid-point of B C . The perpendiculars from D to A B and A C are equal. Prove that the triangle is isosceles.

A B C is a triangle and D is the mid-point of B C . The perpendiculars from D to A B and A C are equal. Prove that the triangle is isosceles.

The sum of the perimeters of a square and a circle is given. Show that the sum of their areas is minimum when the length of a side of the square is equal to the diameter of the circle.

If the bisector of the vertical angle of a triangle bisects the base of the triangle. then the triangle is isosceles. GIVEN : triangle A B C in which A D is the bisector of angle A meeting B C in D such that B D=DC TO PROVE : triangleA B C is an isosceles triangle.

A B C is a triangle is which B E and C F are, respectively, the perpendiculars to the sides A C and A B . If B E=C F , prove that A B C is isosceles.

A B C is a triangle is which B E and C F are, respectively, the perpendiculars to the sides A C and A B . If B E=C F , prove that A B C is isosceles.