If `tan ptheta+cotqtheta=0`, then the genera value of theta is (A) `((2n-1)pi)/(2(p-q))` (B) `(npi)/(p-q)` (C) `(npi)/(p+q)` (D) `((2n+1)pi)/(2(p-q))`

If sintheta=1/2a n dcostheta=-(sqrt(3))/2, then the general value of theta is (n in Z)dot (a) 2npi+(5pi)/6 (b) 2npi+pi/6 (c)2npi+(7pi)/6 (d) 2npi+pi/4

If alpha,beta, gamma re the roots of the equations x^3+px^2+2x+p=0 then the general value of tan^-1 alpha+tan^-1 beta+tan^-1 gamma is (A) npi (B) (npi)/2 (C) (2n+1) pi/2 (D) dependent upon the value of p.

If cos p theta+cos q theta=0 , then prove that the different values of theta are in A.P. with common difference 2pi// (p pm q) .

If sin^3theta+sinthetacos^2theta=1,t h e ntheta is equal to (n in Z) (a) 2npi (b) 2npi+pi/2 (c) 2npi-pi/2 (d) npi

The roots of the equation (q-r)x^2+(r-p)x+p-q=0 are (A) (r-p)/(q-r),1 (B) (p-q)/(q-r),1 (C) (q-r)/(p-q),1 (D) (r-p)/(p-q),1

The value of lim_(x to1)(p/(1-x^p)-q/(1-x^q)),p ,q , in N , equal (a) (p+q)/2 (b) (p q)/2 (c) (p-q)/2 (d) sqrt(p/q)

A general solution of tan^2theta+cos2theta=1 is (n in Z) npi=pi/4 (b) 2npi+pi/4 npi+pi/4 (d) npi

If tan theta = p/q then (p sin theta - q cos theta)/(p sin theta + q cos theta)=

If p > q > 0a n dp r < -1 < q r , then find the value of tan^(-1)((p-q)/(1+p q))+tan^(-1)((q-r)/(1+q r))+tan^(-1)((r-p)/(1+r p)) .

If the line xcostheta+ysintheta=P is the normal to the curve (x+a)y=1, then show theta in (2npi+pi/2,(2n+1)pi)uu(2npi+(3pi)/2,(2n+2)pi),n in Z