A solution of `sin^-1 (1) -sin^-1 (sqrt(3)/x^2)- pi/6 =0` is (A) `x=-sqrt(2)` (B) `x=sqrt(2)` (C) `x=2` (D) `x= 1/sqrt(2)`

(sin^(-1)x)/(sqrt(1-x^(2))

Solve the equation sin^(-1)6 x+sin^(-1)6sqrt(3)x=(-pi)/2dot

Solve the equation sin^(-1)6 x+sin^(-1)6sqrt(3)x=(-pi)/2dot

Solve the equation sin^(-1)x+sin^(-1)6sqrt(3)x=(-pi)/2dot

lim_(xrarr1^(-)) (sqrtpi-sqrt(2sin^-1x))/sqrt(1-x)= (A) sqrt(2/pi) (B) sqrt(pi/2) (C) 1/pi (D) sqrt(1/pi)

The value of ("lim")_(xto1/(sqrt(2))) ((x-"cos" (sin^(-1)x))/ (1-tan(sin^(-1)x))) is (a) -1/(sqrt(2)) (b) 1/(sqrt(2)) (c) sqrt(2) (d) -sqrt(2)

Solve the equations. sin(tan^(-1)x),|x|<1 (A) x/(sqrt(1-x^2)) (B) 1/(sqrt(1-x^2)) (C) 1/(sqrt(1+x^2)) (D) x/(sqrt(1+x^2))

If cos^-1 ((x^2-1)/(x^2+1))+ tan^-1 ((2x)/(x^2-1)) = (2pi)/3 , then x equal to (A) sqrt(3) (B) 2+sqrt(3) (C) 2-sqrt(3) (D) -sqrt(3)

If cos^-1 ((x^2-1)/(x^2+1))+ tan^-1 ((2x)/(x^2-1)) = (2pi)/3 , then x equal to (A) sqrt(3) (B) 2+sqrt(3) (C) 2-sqrt(3) (D) -sqrt(3)

lim_(x to 0) (sin^(2) x)/(sqrt(2)-sqrt(1+cos x))= (A) sqrt(2) (B) 2 (C) 4 (D) 4sqrt(2)