Find `sum_(k=1)^ntan^(- 1)(2k)/(2+k^2+k^4)`

If sum_(k=1)^(k=n)tan^(- 1)((2k)/(2+k^2+k^4))=tan^(- 1)(6/7), then the value of 'n' is equal to

sum_(k=0)^(5)(-1)^(k)2k

Evaluate sum_(k=1)^(11)(2+3^k)

Find the sum_(k=1)^(oo) sum_(n=1)^(oo)k/(2^(n+k)) .

sum _(k=1)^(n) tan^(-1). 1/(1+k+k^(2)) is equal to

The sum sum_(k=1)^oocot^(-1)(2k^2) equals

If for n in N ,sum_(k=0)^(2n)(-1)^k(^(2n)C_k)^2=A , then find the value of sum_(k=0)^(2n)(-1)^k(k-2n)(^(2n)C_k)^2dot

If the value of the sum n^(2) + n - sum_(k = 1)^(n) (2k^(3)+ 8k^(2) + 6k - 1)/(k^(2) + 4k + 3) as n tends to infinity can be expressed in the form (p)/(q) find the least value of (p + q) where p, q in N

Evaluate sum_(k=0)^(5)k^(2)

Let S_n=sum_(k=0)^n n/(n^2+k n+k^2) and T_n=sum_(k=0)^(n-1)n/(n^2+k n+k^2) ,for n=1,2,3,......., then