Find the sum `tan^-1 (1/(3+3.1+1^2))+tan^-1 (1/(3+3.2+2^2))+…+tan^-1 (1/(3+3n+n^2))`

Find the sum tan^-1 (x/ (1+1.2x^2))+tan^-1 (x/(1+2.3x^2))+…+tan^-1 (x/(1+n(n+1)x^2)) xgt0

Sum the series tan^-1 (x/(1+1*2x^2))+tan^-1 (x/(1+2*3x^2))+…+tan^-1 (x/(1+n*(n+1)x^2))

Sum the following series to infinity : tan^(-1)(1/(1+1+1^2))+tan^(-1)(1/(1+2+2^2))+tan^(-1)(1/(1+3+3^2))+.................

Evaluate tan^(-1).(1)/(2)+ tan^(-1).(1)/(3) .

Find the sum series: tan^-1 (1/3)+tan^-1 (1/7)+tan^-1(1/13)+…to oo

Find the sum series: tan^-1 (1/3)+tan^-1 (1/7)+tan^-1(1/13)+…to oo

Find the sum of each of the following series :(i) tan^-1(1/(x^2+x+1))+tan^-1 (1/(x^2+3x+3))+tan^-1(1/(x^2+5X+7))+tan^-1(1/x^2+7x+13)) ......upto n.

Find the sum of each of the following series :(i) tan^-1(1/(x^2+x+1))+tan^-1 (1/(x^2+3x+3))+tan^-1(1/(x^2+5X+7))+tan^-1(1/x^2+7x+13)) ......upto n.

If S= tan^-1 (1/(n^2+n+1))+tan^-1 (1/(n^2+3n+3))+…+tan^-1 (1/(1+(n+19)(n+20))) then tan S is equal to (A) 20/(401+20n) (B) n/(n^2+20n+1) (C) n(401+20n) (D) 20/(n^2+n-1)

The sum tan^(-1).(1)/(1+x+x^2)+tan^(-1).(1/(3+3x+x^2))+tan^(-1).(1/(7+5x+x^2))+tan^(-1)(1/(13+7x+x^2)) of first 100 terms of the series is