Sum ot n terms the series `sin^3theta+sin^3 3theta+sin^3 5 theta+…`

Find the sum to n terms of the series sin^3 theta +1/3 sin^3 3theta+1/3^2sin^3 9theta+1/3^3 sin^3 27theta+…

Sum to terms of the series sintheta sin2theta + sin2thetasin3theta + sin3theta sin4theta +..... is equal to

Sum to n terms the series costheta-sin2theta-cos3theta+sin4theta+cos5theta-……

Solve: sin3theta=sin2theta

If 4n theta = pi , then sin^2 theta+ sin^2 3theta + sin^2 5theta +.... 2n terms is equal to:(1) n , (2) 2n . (3) 3n (4) n^2

Find the sum of the series sintheta- (sin2theta)/(2!)+(sin3theta)/(3!)-… to oo

Prove that ( cos theta + cos 2 theta + cos 3 theta + cos 4 theta)/(sin theta + sin 2 theta + sin 3 theta + sin 4 theta)= cot ""(5theta)/(2).

Find the sum sintheta+x sin 2theta+x^2sin 3theta+… to oo

Find the sum of n terms of the series sqrt(1-sin2theta)+(sqrt(1-sin4theta)+sqrt(1-sin6theta)+…

sin^(3)theta + sin theta - sin theta cos^(2)theta =