If S= tan^-1 (1/(n^2+n+1))+tan^-1 (1/(n^...

If `S= tan^-1 (1/(n^2+n+1))+tan^-1 (1/(n^2+3n+3))+…+tan^-1 (1/(1+(n+19)(n+20)))` then tan S is equal to `(A) 20/(401+20n) (B) n/(n^2+20n+1) (C) n(401+20n) (D) 20/(n^2+n-1)`

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