In a triangle ABC, medians AD and BE are drawn. If `AD=4, angleDAB=(pi)/(6) and angleABE=(pi)/(3)` then the area of the triangle ABC is :

In a triangle ABC, medians AD and BE are deawn. IF AD= 4, angle D AB=(pi)/(6) and angle ABE=(pi)/(3), then the area of the trianlge ABC is-

In a triangle ABC, medians AD and CE are drawn. If AD=5, angle DAC=pi/8 and angle ACE=pi/4 then the area of the triangle ABC is equal to (5a)/b, then a+b is equal to

In triangle ABC medians AD and CE are drawn, if AD=5, angleDAC= pi/8 and angleACE=pi/4 , then the area of triangle ABC is equal to a. 25/8 b. 25/3 c. 25/18 d. 10/3

ABC is a triangle whose medians AD and BE are perpendicular to each other. If AD=p and BE = q then area of triangleABC is

In a triangle ABC with altitude AD, angleBAC=45^(@), DB=3 and CD=2 . The area of the triangle ABC is :

If in a triangleABC, A=pi/3 and AD is the median, then

In a triangle ABC with altitude AD , angleBAC=45^(@), DB=3 and CD=2 . The area of the triangle ABC is : (a) 6 (b) 15 (c) 15/4 (d) 12

In triangle ABC, angle B is right angled, AC=2 and A(2,2), B(1,3) then the length of the median AD is

In a Delta ABC, a =2b and |A-B| =(pi)/(3). Determine the angleC.

In a !ABC the length of the median AD to the side BC is 4 units. If angleA=60^(@) and the area of the triangle is 2sqrt3 sq. units. The length of side BC, is