If `0ltxltpi` and `cosx + sinx =1/2` , then `tanx` is (1) `(4-sqrt(7))/3` (2) `-(4+sqrt(7))/3` ( 3) `(1+sqrt(7))/4` (4) `(1-sqrt(7))/4`

If sinx+cosx=(sqrt(7))/2, where x in 1s t quadrant, then tanx/2 is equal to (a) (3-sqrt(7))/3 (b) (sqrt(7)-2)/3 (c) (4-sqrt(7))/4 (d) none of these

(sqrt(7)+2sqrt(3))(sqrt(7)-2sqrt(3))

Prove that (1)/(sqrt(7))=(1)/(sqrt(7))times(sqrt(7))/(sqrt(7))

Simplify: -sqrt((-7)/(4))-sqrt((-1)/(7))

1/(sqrt(7)+sqrt(3))\times (sqrt(7)-sqrt(3))/(sqrt(7)-sqrt(3))

Simplify : 7sqrt((1)/(3)) -2(1)/(3) sqrt((1)/(3)) +3 sqrt( 147)

AB is a vertical pole with B at the ground level and A at the top. A man finds that the angle of elevation of the point A from a certain point C on the ground is 60o . He moves away from the pole along the line BC to a point D such that C D""=""7""m . From D the angle of elevation of the point A is 45o . Then the height of the pole is (1) (7sqrt(3))/2 1/(sqrt(3)-1)m (2) (7sqrt(3))/2 sqrt(3)+1m (3) (7sqrt(3))/2 sqrt(3)-1m (4) (7sqrt(3))/2 sqrt(3)+1m

Prove that tan [7(1)/(2)]^0 = (sqrt(3) - sqrt(2)) (sqrt(2) - 1) .

A line passes through point P(4,5) and makes 30^@ with X-axis. Then the coordinates of the point which is at distance of 4 unit on either side of P is : a. (4-2sqrt(3),7) , (4+2sqrt(3),7) b. (4+2sqrt(3),7) , (4-2sqrt(3),7) c. (4+2sqrt(3),7) , (4-2sqrt(3),3) d. (4-2sqrt(3),7) , (4-2sqrt(3),7)

Show that : (1)/(3-2sqrt(2))- (1)/(2sqrt(2)-sqrt(7)) + (1)/(sqrt(7)-sqrt(6))-(1)/(sqrt(6)-sqrt(5))+(1)/(sqrt(5)-2)=5 .