If `cos(A+B) sin (C-D) = cos (A-B) sin (C+D)`, then show that `tan A tan B tan C + tan D =0`

Statement:1 If cos(A+B)sin( C +D) = cos(A-B) sin(C-D) , then the values of cotAcotBcotC is cotD. And Statement:2: If cos(A+B) sin(C+D)= cos(A-B) sin(C-D) then the value of tanAtanBtanC is tanD.

If cos(A+B)sin(C-D)="cos"(A-B)"sin"(C+D) , then write the value of t a n A t a n B t a n Cdot

If cos(A+B)sin(C+D)=cos(A-B)sin(C-D) , prove that cot A cot B cot C=cotD .

(cos(A-B))/(cos(A+B))+cos(C+D)/(cos(C-D))=0 => tan A tan B tan C tan D =

If in a DeltaABC, sin A, sin B, sin C are in A.P., show that 3 tan, A/2 tan, C/2 = 1

Given that A = B +C. prove that tan A - tan B - tan C = tan A tan B tan C.

In a Delta ABC , if cosA cos B cos C= (sqrt3-1)/(8) and sin A sin B sin C= (3+ sqrt3)/(8) , then The value of tan A tan B tanC is

In a Delta ABC , if cosA cos B cos C= (sqrt3-1)/(8) and sin A sin B sin C= (3+ sqrt3)/(8) , then the respective values of tan A, tan B and tanC are

In a Delta ABC , if cosA cos B cos C= (sqrt3-1)/(8) and sin A sin B sin C= (3+ sqrt3)/(8) , then The value of tan A + tan B + tan C is

In a triangle tan A+ tan B + tan C=6 and tan A tan B= 2, then the values of tan A, tan B and tan C are