If `(2^n+1)theta=pi` then `2^n costheta cos2theta cos2^2 theta .......cos 2^(n-1) theta=`

costheta+cos2theta+cos3theta+.......+cos(n-1)theta+cosntheta=

For all n in N, cos theta cos 2theta cos 4theta ....cos2^(n-1)theta equals to

If theta = (pi)/(2 ^(n) +1) prove that 2 ^(n) cos theta cos 2 theta cos 2 ^(2) theta…. Cos 2 ^(n -1) theta =1

If theta=pi/(2^n+1) , prove that: 2^ncosthetacos2thetacos2^2 cos2^(n-1)theta=1.

Using induction, prove that cos theta · cos 2theta · cos 2^2 theta. ... cos 2^(n-1) theta =(sin2^n theta)/(2^n sin theta)

Prove that: (2cos2^ntheta+1)/(2costheta+1)=(2costheta-1)(2cos2theta-1)(2cos2^2theta-1) ...(2cos2^(n-1)theta-1)

Prove that : (2 cos 2^n theta + 1)/(2 cos theta +1) = (2 cos theta -1) (2 cos 2theta -1) (2 cos 2^2 theta -1) … (2 cos 2^(n-1) theta -1)

Find the value of cos theta. cos 2theta. cos 2^(2)theta . cos 2^(3)theta"……." cos 2^(n-1) theta is

If theta=(pi)/(7), show that cos theta cos 2theta cos 3 theta = (1)/(8) .

(1+sin 2theta+cos 2theta)/(1+sin2 theta-cos 2 theta) =