If `3tan(theta-15^(@))- tan(theta+15^(@))=0`. Find `theta`.

Solve: 3tan(theta-15^(@))=tan(theta+15^(@))

If 3tan(theta-15^0)=tan(theta+15^0), then theta is equal to n in Z) n pi+pi/4 (b) npi+pi/8 npi+pi/3 (d) none of these

The point (3tan (theta +60^(@)),2 tan(theta +30^(@))) lies on the conic, then its centre is (theta is the parameter)

Solve 3tan^(2) theta-2 sin theta=0 .

If cos theta = 0.75, tan theta =

The general solution of equation 3 tan(theta - 15^o) = tan(theta+15^o) is:

If tan theta + tan (60^@+ theta) + tan (120^@ + theta)=3 then theta =

theta = tan^(-1) (2 tan^(2) theta) - tan^(-1) ((1)/(3) tan theta) " then " tan theta=

Prove that (tan^(2)2theta-tan^(2)theta)/(1-tan^(2)2thetatan^(2)theta)=tan 3 theta tan theta .

If 1+ tan^(2) theta = sec^(2) theta then find (sec theta + tan theta)