If in a `triangleABC, a=1/(sqrt(6)-sqrt(2)), b=1/(sqrt(6) + sqrt(2)), C=60^(@)`, then prove that `c=sqrt(3)/2`.

यदि triangleABC में (If इन triangleABC), a = (1)/(sqrt(6)-sqrt(2)), b = (1)/(sqrt(6)+sqrt(2)), C = 60^(@) तो सिद्ध कीजिए कि (Prove that) c = (sqrt(4))/(2) .

(sqrt(6+2sqrt(5)))(sqrt(6-2sqrt(5)))

If a=sqrt(3),b=1/2(sqrt(6)+sqrt(2))dot and c=2, then find /_A

If in triangleABC, a=2sqrt(3), b=3sqrt(2) and angleB = 60^(@) , then find the measure of angleC .

Simplify : (sqrt(2))/(sqrt(6)-sqrt(2))- (sqrt(3))/(sqrt(6)+sqrt(2))

(4(sqrt(6) + sqrt(2)))/(sqrt(6) - sqrt(2)) - (2 + sqrt(3))/(2 - sqrt(3)) =

In any triangleABC , prove that (sqrt(sinA)-sqrt(sinB))/(sqrt(sinA) + sqrt(sinB)) = (a+b-2sqrt(ab))/(a-b) [Hint : (a-b)^(2) = a^(2)+b^(2)-2ab ]

(sqrt(2) + 1)^(6) - (sqrt(2) -1)^(6) is equal to

In a DeltaABC if a = 2, b=sqrt(6),c=sqrt(3)+1 , then cos A=

In triangleABC , if a^(2)+b^(2)+c^(2)=ac+ab sqrt(3) , then