`tan""(1)/(2)[sin^(-1)""(2x)/(1+x^(2))+cos^(-1)""(1-y^(2))/(1+y^(2))],|x|lt1,y gt0 and xy lt 1`

Find the value of: tan(1/2 [sin^(-1)((2x)/(1+x^2))+cos^(-1)((1-y^2)/(1+y^2))]),|x| 0 and x y < 1

Find the value of the following: tan [1/2[sin^(-1) ((2x)/(1+x^2))+cos^(-1) ((1-y^2)/(1+y^2))]], |x| 0 and x y < 1 .

Find the value of: tan1/2[sin^(-1)(2x)/(1+x^2)+cos^(-1)(1-y^2)/(1+y^2)],|x| 0 and x y" "<" "1

y = cos ^(-1)((1 - x^(2))/(1+ x^(2))) 0 lt x lt 1

y = cos ^(-1)((2x)/(1 +x^(2))),-1 lt x lt1 . find dy/dx

If y=log((1-x^(2))/(1+x^(2))),|x|lt1 , then (dy)/(dx) =

Find the value of tan { 1/2 sin^(-1) ((2x)/(1+x^(2))) + 1/2 cos^(-1) ((1-y^(2))/(1+ y^(2)))}

y = sin ^(-1)((1 - x^(2))/(1+ x^(2))) 0 lt x lt 1 find dy/dx

If |a|lt1|b|lt1and|x|lt1 then the solution of sin^(-1)((2a)/(1+a^(2)))-cos^(-1)((1-b^(2))/(1+b^(2)))=tan^(-1)((2x)/(1-x^(2))) is

tan^(- 1) (1/(x+y)) +tan^(- 1) (y/(x^2+x y+1)) =cot^(- 1)x