In a `DeltaABC`, prove that : `tanA+tanB+tanC= tanA tanB tanC`

tanA +tanB + tanC = tanA tanB tanC if

If tanA+tanB+tanC=tanAtanBtanC then

In DeltaABC , prove that: tanA/2tanB/2+tanB/2tanC/2+tanC/2tanA/2=1

In DeltaABC , tanA+tanB+tanC=tanAtanBtanC

If A+B+C= pi/2 , show that : tanA tanB + tanB tanC + tanC tanA=1

In DeltaABC , prove that: (b-c)/(a)=(tanB/2-tanC/2)/(tanB/2+tanC/2)

In DeltaABC , prove that: a/(b+c)=(1-tanB/2tanC/2)/(1+tanB/2tanC/2)

In DeltaABC , prove that: tanA/2.tanB/2.tanC/2=sqrt((1-a/s)(1-b/s)(1-c/s))

Statement-1: In an acute angled triangle minimum value of tan alpha + tanbeta + tan gamma is 3sqrt(3) . And Statement-2: If a,b,c are three positive real numbers then (a+b+c)/3 ge sqrt(abc) into in a triangleABC , tanA+ tanB + tanC= tanA. tanB.tanC

In an acute-angled triangle ABC, tanA+tanB+tanC=tanAtanBtanC , then tanAtanBtanC =