ABCD is a parallelogram E and F are the middle points of AD and CD respectively. Express `vec(BE) and vec(BF)` in terms of `veca and vecb , where vec(BA)=vecaand vec(BC)=vecb`.

A B C D is a parallelogram. If La n dM are the mid-points of B Ca n dD C respectively, then express vec A La n d vec A M in terms of vec A Ba n d vec A D . Also, prove that vec A L+ vec A M=3/2 vec A Cdot

A B C D is a parallelogram. If L and M are the mid-points of B C and D C respectively, then express vec A L and vec A M in terms of vec A B and vec A D . Also, prove that vec A L+ vec A M=3/2 vec A Cdot

If ABCD is a parallelogram, then vec(AC) - vec(BD) =

If D, E, F are respectively the mid-points of AB, AC and BC respectively in a Delta ABC, " then " vec (BE) + vec(AF) =

Vectors drawn the origin O to the points A , Ba n d C are respectively vec a , vec ba n d vec4a- vec3bdot find vec A Ca n d vec B Cdot

If veca and vecb are position vectors of A and B respectively, then the position vector of a point C in vec(AB) produced such that vec(AC) =2015 vec(AB) is

If veca.vecb=0 and vecaxxvecb=0 prove that veca=vec0 or vecb=vec0 .

If D,E and F are the mid-points of the sides BC, CA and AB respectively of a triangle ABC and lambda is scalar, such that vec(AD) + 2/3vec(BE)+1/3vec(CF)=lambdavec(AC) , then lambda is equal to

The position vector of foru points A,B,C,D are veca, vecb, 2veca+3vecb and veca-2vecb respectively. Expess the vectors vec(AC), vec(DB), vec(BC) and vec(CA) in terms of veca and vecb .

If ABCDEF is a regular hexagon with vec(AB) = veca and vec(BC)= vecb, then vec(CE) equals