In trapezium PQRS, given that `QR|| PS and 2QR=PS. If ``vec(PQ)=veca,vec(QR)=vecb and vec(RS)=vecc`, express `veca` in terms `vecb and vecc`

If vecaxxvecb=vecc,vecb xx vecc=veca, where vecc != vec0, then

veca+vecb+vecc=vec0, |veca|=3, |vecb|=5,|vecc|=9 ,find the angle between veca and vecc .

Prove that [ veca+ vecb , vecb+ vecc , vecc+ veca]=2[ veca , vecb , vecc] .

given that veca. vecb = veca.vecc, veca xx vecb= veca xx vecc and veca is not a zero vector. Show that vecb=vecc .

If veca +vecb +vecc =vec0, |veca| =3 , |vecb|=5 and |vecc| =7 , then the angle between veca and vecb is

If PQRS is a quadrilteral such that vec(PQ)=veca,vec(PS)=vecb and vec(PR)=x veca+yvecb show that the area of the quadrilateral PQRS is 1/2|(xy||vecaxxvecb|

If veca, vecb, vecc are vectors such that veca.vecb=0 and veca + vecb = vecc then:

if veca , vecb ,vecc are three vectors such that veca +vecb + vecc = vec0 then

Prove that the three points veca-2vecb+3vecc, vec(2a)+3vecb-4vecc and -7vecb+10vecc are collinear

[ veca + vecb vecb + vecc vecc + veca ]=[ veca vecb vecc ] , then