Vectors `veca and vecb` are non-collinear. Find for what value of x vectors `vecc=(x-2)veca+vecb and vecd=(2x+1)veca-vecb` are collinear ?

The vectors veca and vecb are non collinear. Find for what value of x the vectors vecc=(x-2)veca+vecb and vecd=(2x+1) veca-vecb are collinear.?

If vecaandvecb are non-collinear vector, find the value of x such that the vectors vecalpha=(x-2)veca+vecbandvecbeta=(3+2x)veca-2vecb are collinear.

If veca and vecb are two non collinear vectors and vecu = veca-(veca.vecb).vecb and vecv=veca x vecb then vecv is

Let veca and vecb be two non-collinear unit vectors. If vecu=veca-(veca.vecb)vecb and vecv=vecaxxvecb , then |vecv| is

i. If veca, vecb and vecc are non-coplanar vectors, prove that vectors 3veca-7vecb-4vecc, 3veca-2vecb+vecc and veca+vecb+2vecc are coplanar.

Given three vectors e veca, vecb and vecc two of which are non-collinear. Futrther if (veca + vecb) is collinear with vecc, (vecb +vecc) is collinear with veca, |veca|=|vecb|=|vecc|=sqrt2 find the value of veca. Vecb + vecb.vecc+vecc.veca

If veca and vecb are non - zero vectors such that |veca + vecb| = |veca - 2vecb| then

If veca and vecb are two non collinear unit vectors and |veca+vecb|=sqrt(3) then find the value of (veca-vecb).(2veca+vecb)

If veca,vecb,vecc are three non zero vectors (no two of which are collinear) such that the pairs of vectors (veca+vecb,vecc) and (vecb+vecc,veca) are colliner, then what is the value of veca+vecb+vecc ? (A) veca is parrallel to vecb (B) vecb (C) vecc (D) vec0

The vectors veca and vecb are not perpendicular and vecc and vecd are two vectors satisfying : vecbxxvecc=vecbxxvecd and veca.vecd=0. Then the vecd is equal to (A) vecc+(veca.vecc)/(veca.vecb)vecb (B) vecb+(vecb.vecc)/(veca.vecb)vecc (C) vecc-(veca.vecc)/(veca.vecb)vecb (D) vecb-(vecb.vecc)/(veca.vecb)vecc