Given `vec(a)` is perpendicular to `vecb+vecc`, `vecb ` is perpendicular to `vecc+veca` and `vecc` is perpendicular to `veca+vecb`. If `|veca|=1, |vecb|=2, |vecc|=3`, find `|veca+vecb+vecc|`

Let veca vecb and vecc be pairwise mutually perpendicular vectors, such that |veca|=1, |vecb|=2, |vecc| = 2 , the find the length of veca +vecb + vecc .

Let veca vecb and vecc be pairwise mutually perpendicular vectors, such that |veca|=1, |vecb|=2, |vecc| = 2 , the find the length of veca +vecb + vecc .

If veca, vecb and vecc are vectors such that |veca|=3,|vecb|=4 and |vecc|=5 and (veca+vecb) is perpendicular to vecc,(vecb+vecc) is perpendicular to veca and (vecc+veca) is perpendicular to vecb then |veca+vecb+vecc|= (A) 4sqrt(3) (B) 5sqrt(2) (C) 2 (D) 12

The vector (veca.vecb)vecc-(veca.vecc)vecb is perpendicular to

Let veca , vecb,vecc be three vectors such that veca bot ( vecb + vecc), vecb bot ( vecc + veca) and vecc bot ( veca + vecb) , " if " |veca| =1 , |vecb| =2 , |vecc| =3 , " then " | veca + vecb + vecc| is,

If veca, vecb,vecc are unit vectors such that veca is perpendicular to the plane of vecb, vecc and the angle between vecb,vecc is pi/3 , then |veca+vecb+vecc|=

if veca xx vecb = vecc ,vecb xx vecc = veca , " where " vecc ne vec0 then (a) |veca|= |vecc| (b) |veca|= |vecb| (c) |vecb|=1 (d) |veca|=|vecb|= |vecc|=1

veca+vecb+vecc=vec0, |veca|=3, |vecb|=5,|vecc|=9 ,find the angle between veca and vecc .

The value of [(veca-vecb, vecb-vecc, vecc-veca)] , where |veca|=1, |vecb|=5, |vecc|=3 , is

If veca and vecb be two non collinear vectors such that veca=vecc+vecd , where vecc is parallel to vecb and vecd is perpendicular to vecb obtain expression for vecc and vecd in terms of veca and vecb as: vecd= veca- ((veca.vecb)vecb)/b^2,vecc= ((veca.vecb)vecb)/b^2