`2(b ccosA+c acosB+a bcosC)=a^2+b^2+c^2`

2(bc cosA+c acosB+a bcosC)=a^2+b^2+c^2

In any Delta A B C , prove that: 2(bc cosA+cacosB+a bcosC)=a^2+b^2+c^2

In any Delta A B C , prove that: (cosA)/(bcosC+c cosB)+(cosB)/(c cosA+acosC)+(cosC)/(acosB+bcosA)=(a^2+b^2+c^2)/(2a b c)

In any Delta A B C , prove that: (cos A)/a+(cos B)/b+(cos C)/c=(a^2+b^2+c^2)/(2a b c)

Show that: |b^2+c^2a b a c b a c^2+a^2b cc a c b a^2+b^2|=4a^2\ b^2\ c^2 .

Prove that a(bcosC-ccosB)=b^2-c^2

In a DeltaA B C , prove the following : c\ (acosB-bcosA)=a^2-b^2dot

Show that: |b^2+c^2a b a c b a c^2+a^2b c c a c b a^2+b^2|=4a^2b^2c^2

Show that: |(b+c)^2b a c a a b(c+a)^2c b a c b c(a+b)^2|=2a b c(a+b+c)^3

Using the property of determinants and without expanding, prove that: |[-a^2,a b, a c],[ b a, -b^2,b c],[c a, c b,-c^2]|=4a^2b^2c^2