A paticle acted on by constant forces `4hati+hatj-3hatk and 3hati+hatj-hatk` is displaced from the point `hati+2hatj+3hatk to 5hati+4hatj+hatk`. Find the work done

A particle acted upon by constant forces 4hati +hatj- 4 hatk and 3hati + hatj - hatk is displacment from the point hati+ 2hatj+ hatk to point 5hati + 4hatj +hatk .Total work done by the forces in SI unit is :

Find the angle between the vectors 4hati-2hatj+4hatk and 3hati-6hatj-2hatk.

If vecF = 3hati + 4hatj+5hatk and vecS=6hati +2hatj+5hatk , the find the work done.

Work done by a force F=(hati+2hatj+3hatk) acting on a particle in displacing it from the point r_(1)=hati+hatj+hatk to the point r_(2)=hati-hatj+hat2k is

Two forces -hati+2hatj-hatk and 2hati-5hatj+6hatk act on a particfle whose position vector is 4hati-3hatj+2hatk and displace it to another point whose positon vector is 6hati+hatj-3hatk . Find the total work done by the force.

Unit vector perpnicular to vector A=-3hati-2hatj -3hatk and 2hati + 4hatj +6hatk is

If vecF=3hati-4hatj+5hatk " and " vecS=6hati+2hatj+5hatk , the find the work done.

If the vectors 2hati-hatj+hatk,hati+2hatj-3hatk and 3hati+ahatj+5hatk are coplanar, the prove that a=-4.

A particle moves from position 3hati+2hatj-6hatk to 14hati+13hatj+9hatk due to a uniform force of (4hati+hatj+3hatk)N . If the displacement in meters then work done will be

If veca=3hati+hatj-4hatk and vecb=6hati+5hatj-2hatk find |veca Xvecb|