show that `|veca|vecb+|vecb|veca` is a perpendicular to `|veca|vecb-|vecb|veca` .for any two non-zero vectors `veca and vecb`

Show that |veca|vecb+|vecb|veca is perpendicular to |veca|vecb-|vecb|veca for any two non zero vectors veca and vecb.

Show that |veca|vecb+|vecb|veca is perpendicular to |veca|vecb-|vecb|veca for any two non zero vectors veca and vecb.

The vector (veca.vecb)vecc-(veca.vecc)vecb is perpendicular to

If veca and vecb are two unit vectors such that veca+2vecb and 5veca-4vecb are perpendicular to each other, then the angle between veca and vecb is

If veca, vecb, vecc non-zero vectors such that veca is perpendicular to vecb and vecc and |veca|=1, |vecb|=2, |vecc|=1, vecb.vecc=1 . There is a non-zero vector coplanar with veca+vecb and 2vecb-vecc and vecd.veca=1 , then the minimum value of |vecd| is

If veca , vecb are unit vectors such that the vector veca + 3vecb is peependicular to 7 veca - vecb and veca -4vecb is prependicular to 7 veca -2vecb then the angle between veca and vecb is

The formula (veca + vecb)^(2)= (veca)^(2) + (vecb)^(2) + 2veca xx vecb valid for non zero vectors veca and vecb .

If veca an vecb are perpendicular vectors, |veca+vecb|=13 and |veca|=5 , find the value of |vecb| .

If veca and vecb be two non collinear vectors such that veca=vecc+vecd , where vecc is parallel to vecb and vecd is perpendicular to vecb obtain expression for vecc and vecd in terms of veca and vecb as: vecd= veca- ((veca.vecb)vecb)/b^2,vecc= ((veca.vecb)vecb)/b^2

STATEMENT-1 Let veca,vecb bo two vectors such that veca.vecb=0 , then veca and vecb are perpendicular. And STATEMENT-2 Two non-zero vectors are perpendicular if and only if their dot product is zero.