If `veca.vecb=0 and vecaxxvecb=0` prove that `veca=vec0 or vecb=vec0`.

If veca= vecP + vecq, vecP xx vecb = vec0 and vecq. vecb =0 then prove that (vecbxx(veca xx vecb))/(vecb.vecb)=vecq

If vecasxxvecb=0 and veca.vecb=0 then (A) veca_|_vecb (B) veca||vecb (C) veca=0 and vecb=0 (D) veca=0 or vecb=0

If vecaxxvecb=vecbxxvecc!=vec0, then prove that veca+vecc=tvecb , where t is a scalar.

If veca,vecb and vecc are unit vectors such that veca+vecb+vecc=vec0 then the value of veca.vecb+vecb.vecc+vecc.veca is a) 1 b) 0 c) 3 d) -3/2

Given that veca.vecb=0 and veca xx vecb=0 . What can you conclude about the vectors veca and vecb .

If veca,vecb and vecc are unit vectors such that veca + vecb + vecc= 0 , then prove that veca.vecb+vecb.vecc+vecc.veca=-3/2

If veca,vecb, vecc are three vectors such that veca + vecb +vecc =vec0, |veca| =1 |vecb| =2, | vecc| =3 , then veca.vecb + vecb .vecc + vecc.veca is equal to

If veca , vecb and vec(c ) are there vectors such that veca + vecb = vec(C ) and further a^2 +b^2 =c ^2 find the angle between veca and vecb ?

If the vectors veca, vecb, and vecc are coplanar show that |(veca,vecb,vecc),(veca.veca, veca.vecb,veca.vecc),(vecb.veca,vecb.vecb,vecb.vecc)|=0

If the vectors veca,vecb,vecc form the sides BC,CA and AB respectively of a triangle ABC then (A) veca.(vecbxxvecc)=vec0 (B) vecaxx(vecbxvecc)=vec0 (C) veca.vecb=vecc=vecc=veca.a!=0 (D) vecaxxvecb+vecbxxvecc+veccxxvecavec0