A solution of the vector equation `vecrxxvecb=vecaxxvecb`, where `veca, vecb` are two given vectors is
where `lamda` is a parameter.

Solve: vecrxxvecb=veca, where veca and vecb are given vectors such that veca.vecb=0 .

Solve for vec x,vecx xx vec b=veca , where veca,vecb are two given vectors such that veca is perpendicular to vecb .

Find vector vecr if vecr.veca=m and vecrxxvecb=vecc, where veca.vecb!=0

Vectors vecA and vecB satisfying the vector equation vecA+ vecB = veca, vecA xx vecB =vecb and vecA.veca=1 . where veca and vecb are given vectosrs, are

If vecaxxvecb=vecc,vecb xx vecc=veca, where vecc != vec0, then

Solve veca.vecr=x, vecb.vecr=y, vecc.vecr=z where veca,vecb,vecc are given non coplasnar vectors.

Show that the equation vecrxxvecb=vec0(vecb!=vec0) has a solution iff veca.vecb!=0 .

The scalars l and m such that lveca + m vecb =vecc, " where " veca, vecb and vecc are given vectors, are equal to

For any two vectors veca and vecb prove that |veca.vecb|<=|veca||vecb|

a,b are the magnitudes of vectors veca & vecb . If vecaxxvecb=0 the value of veca.vecb is