For any four vectors prove that
`(vecbxxvecc).(veca xxvecd)+(vecc xxveca).(vecbxxvecd)+(vecaxxvecb).(veccxxvecd)=0`

Prove that (vecbxxvecc)xx(veccxxveca)=[veca vecb vecc]vecc

Prove that (vecbxxvecc)xx(veccxxveca)=[veca vecb vecc]vecc

For any four vectors, prove that ( veca × vecb )×( vecc × vecd )=[ veca vecc vecd ] vecb −[ vecb vecc vecd ] veca

If veca, vecb, vecc are non-coplanar non-zero vectors, then (vecaxxvecb)xx(vecaxxvecc)+(vecbxxvecc)xx(vecbxxveca)+(veccxxveca)xx(veccxxvecb) is equal to

For vectors veca,vecb,vecc,vecd, vecaxx(vecbxxvecc)=(veca.vecc)vecb-(veca.vecb)vecc and (vecaxxvecb).(veccxxvecd)=(veca.vecc)(vecb.vecd)-(veca.vecd)(vecb.vecc) Now answer the following question: (vecaxxvecb).(veccxxvecd) is equal to (A) veca.(vecbxx(veccxxvecd)) (B) |veca|(vecb.(veccxxvecd)) (C) |vecaxxvecb|.|veccxxvecd| (D) none of these

For vectors veca,vecb,vecc,vecd, vecaxx(vecbxxvecc)=(veca.vecc)vecb-(veca.vecb)vecc and (vecaxxvecb).(veccxxvecd)=(veca.vecc)(vecb.vecd)-(veca.vecd)(vecb.vecc) Now answer the following question: {(vecaxxvecb).xxvecc}.vecd would be equal to (A) veca.(vecbxx(veccxxvecd)) (B) ((vecaxxvecc)xxvecb).vecd (C) (vecaxxvecb).(veccxxvecd) (D) none of these

If veca, vecba and vecc are non- coplanar vecotrs, then prove that |(veca.vecd)(vecbxxvecc)+(vecb.vecd)(veccxxveca)+(vecc.vecd)(vecaxxvecb) is independent of vecd where vecd is a unit vector.

Prove that: [(vecaxxvecb)xx(vecaxxvecc)].vecd=[veca vecb vecc](veca.vecd)

For any three vectors veca,vecb,vecc their product would be a vector if one cross product is folowed by other cross product i.e (vecaxxvecb)xxvecc or (vecbxxvecc)xxveca etc. For any four vectors veca,vecb,vecc,vecd the product would be a vector with the help of sequential cross product or by cross product of two vectors obtained by corss product of two pair i.e. (vecaxx(vecbxxvecc))xxvecd or (vecaxxvecb)xx(veccxxvecd). (vecaxxvecb)xx(veccxxvecd) would be a (A) equally inclined with veca,vecb, vecc, vecd (B) perpendicular with (vecaxxvecb)xxvecc and vecc (C) equally inclined with vecaxxvecb and veccxxvecd (D) none of these

for any four vectors veca,vecb, vecc and vecd prove that vecd. (vecaxx(vecbxx(veccxxvecd)))=(vecb.vecd)[veca vecc vecd]