If veca and vecb be two non collinear ve...

If `veca and vecb` be two non collinear vectors such that `veca=vecc+vecd`, where `vecc` is parallel to `vecb` and `vecd` is perpendicular to `vecb` obtain expression for `vecc and vecd` in terms of `veca and vecb` as: `vecd= veca- ((veca.vecb)vecb)/b^2,vecc= ((veca.vecb)vecb)/b^2`

AI Generated Solution

Similar Questions

Explore conceptually related problems

If veca, vecb, vecc are vectors such that veca.vecb=0 and veca + vecb = vecc then:

If veca,vecb and vecc are non coplaner vectors such that vecbxxvecc=veca , veccxxveca=vecb and vecaxxvecb=vecc then |veca+vecb+vecc| =

If veca, vecb, vecc are any three non coplanar vectors, then [(veca+vecb+vecc, veca-vecc, veca-vecb)] is equal to

If veca, vecb, vecc are three non-zero vectors such that veca + vecb + vecc=0 and m = veca.vecb + vecb.vecc + vecc.veca , then:

The vector (veca.vecb)vecc-(veca.vecc)vecb is perpendicular to

If veca, vecb and vecc are three non-coplanar vectors, then (veca + vecb + vecc). [(veca + vecb) xx (veca + vecc)] equals

If veca,vecbandvecc are unit vectors such that veca+vecb+vecc=0 , then the value of veca.vecb+vecb.vecc+vecc.veca is

If veca , vecb , vecc are unit vectors such that veca+ vecb+ vecc= vec0 find the value of (veca* vecb+ vecb* vecc+ vecc*veca) .

For any four vectors, prove that ( veca × vecb )×( vecc × vecd )=[ veca vecc vecd ] vecb −[ vecb vecc vecd ] veca